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5x^2+6x-4.9=0
a = 5; b = 6; c = -4.9;
Δ = b2-4ac
Δ = 62-4·5·(-4.9)
Δ = 134
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{134}}{2*5}=\frac{-6-\sqrt{134}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{134}}{2*5}=\frac{-6+\sqrt{134}}{10} $
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